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- Registered: 2017-07-24
- Topics: 6
- Posts: 12
1＃ Go Tocould someone help me with my school problem?
a stone is thrown vertically downward from the top of a building leaving the throwers hand with a velocity of 10m/s
(a) what will its velocity be after falling for 2 seconds?
(b) how far will it fall in 2 seconds?
(c) what will be its velocity after falling 10m?
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- Registered: 2017-07-24
- Topics: 15
- Posts: 723
Hello~
As this is not a Naruto related post, I'm afraid I'll have to close this one.
But because education is also important, here:
Given: Initial velocity = Vi = 10m/s
(a) formula = final velocity = Vf = Vi + gt
Vf = 10 + 9.81m/s * 2 seconds
Vf = 10 + 19.62
Vf = 29.62 m/s
(b) formula = h = ViT + 1/2gt^2
h = 10*2 + (9.81*(2^2))/2
h = 20 + 39.24/2
h = 20 + 19.62
s = 39.6m
(c) formula = Vf^2 = Vi^2 + 2gh
Vf^2 = 10^2 + (2 * 9.81 * 10)
Vf^2 = 100 + 196.2
Vf^2 = 296.2
sqrt Vf = sqrt 296.2
Vf = 17.21m/s
There! Good luck
Closing thread.
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